#!/usr/bin/env python
# -*- coding: utf-8 -*-

from __future__ import division

import random
from itertools import chain, islice
import bisect
import math

from mpmath import fsum

# publications used for this file:

# [Kurita1991] Takito Kurita: "An Efficient Agglomerative Clustering Algorithm Using A Heap", Pattern Recognition,
# Volume 24 Issue 3, 1991.
# [Ng1994] Raymond T. Ng, Jiawei Han: Efficient and Effective Clustering Methods for Spatial Data Mining.
# VLDB 1994: 144-155
# [Rangel2016] E. Rangel, W. Hendrix, A. Agrawal, W.-keng Liao, and A. Choudhary, “AGORAS: A Fast Algorithm for
# Estimating Medoids in Large Datasets,” in Proceedings of International Conference on Computational Science (ICCS),
# 2016.
# [Hamerly2003] Greg Hamerly, Charles Elkan, Learning the k in k-means. In proceedings of the seventeenth
# annual conference on neural information processing systems (NIPS), pages 281-288, December 2003.
# [Desgraupes2013] Bernard Desgraupes, Package clusterCrit for R: Clustering Indices, available online at
# https://cran.r-project.org/web/packages/clusterCrit/vignettes/clusterCrit.pdf
# [Greutert2003] Andreas Greutert, "Methoden zur Schätzung der Clusteranzahl", Ausgabe: 29. Oktober 2003.
# Diplomarbeit. ETH Zürich.
# [Frey2007] Brendan J. Frey, Delbert Dueck, "Clustering by Passing Messages Between Data Points",
# Science 16 Feb 2007: Vol. 315, Issue 5814, pp. 972-976
# [Arthur2007] Arthur, D.; Vassilvitskii, S. (2007). "k-means++: the advantages of careful seeding",
# Proceedings of the eighteenth annual ACM-SIAM symposium on Discrete algorithms. Society for Industrial and
# Applied Mathematics Philadelphia, PA, USA. pp. 1027–1035.
# [Hamerly2010] Greg Hamerly, Making k-means even faster In proceedings of the 2010 SIAM international
# conference on data mining (SDM 2010), April 2010.

# for agglomerative clustering, we use [Kurita1991].

# for hierarchical clustering, we use ClaraNS (see [Ng1994]), but we start local searches not with a random sample,
# but with a seed computed via AGORAS (see [Rangel2016]). for clustering without knowing the number of clusters k,
# we use the approach described in [Hamerly2003]. further improvements might be gained through [Frey2007].


def _index(i, j):  # i > j, returns j + sum(1, 2, ..., i - 1)
    # x x x
    # a x x
    # b c x

    # a = 0, b = 1, c = 2
    return j + ((i - 1) * i) // 2


def _robust_min(iterable):
    minimum = None
    for i in iterable:
        if minimum is None or i < minimum:
            minimum = i
    return minimum


def _ordered2(a, cmp):
    iterator = iter(a)

    min_i1 = 0
    min_i2 = 1

    min_x1 = next(iterator)
    min_x2 = next(iterator)

    if not cmp(min_x1, min_x2):
        min_i1, min_i2 = min_i2, min_i1
        min_x1, min_x2 = min_x2, min_x1

    try:
        i = 2
        while True:
            x = next(iterator)
            if cmp(x, min_x1):
                min_x2 = min_x1
                min_i2 = min_i1
                min_x1 = x
                min_i1 = i
            elif cmp(x, min_x2):
                min_x2 = x
                min_i2 = i
            i += 1
    except StopIteration:
        return min_i1, min_x1, min_i2, min_x2


def _smallest2(a):
    return _ordered2(a, lambda x, y: x < y)


def _largest2(a):
    return _ordered2(a, lambda x, y: x > y)


def _components(clusters, n):
    components = [0] * n
    for i, c in enumerate(clusters):
        component_index = i + 1
        for j in c:
            components[j] = component_index
    return components


def _clusters(x, a, k):
    clusters = [[] for _ in range(k)]
    add = [c.append for c in clusters]
    for i, j in enumerate(a):
        add[j](x[i])
    return clusters


def _ratio_bigger_than(a, b):
    # check if (a1 / a2) > (b1 / b2)
    a1, a2 = a
    b1, b2 = b
    return a1 * b2 > b1 * a2


def _pairwise_sum(a, b):
    return [x + y for x, y in zip(a, b)]


class InfiniteSilhouette(Exception):
    # thrown when two clusters have distance 0
    pass


def _silhouette(a, b):
    if a is None:
        # a is infinite, i.e. only one element
        # in the cluster and thus no distances?
        return 0.

    # for the formula, see [Desgraupes2013].
    try:
        s = (b - a) / max(a, b)
    except ZeroDivisionError:  # max(a, b) == 0?
        raise InfiniteSilhouette()

    return s


class PrecomputedDistances(object):
    def __init__(self, distances):
        self._distances = distances

    def distance(self, i, j):
        return self._distances[_index(max(i, j), min(i, j))]

    def matrix(self):
        return self._distances


class LazyDistances(object):
    def __init__(self):
        self._computed = {}

    def distance(self, i, j):
        computed = self._computed
        index = _index(max(i, j), min(i, j))
        d = computed.get(index, None)
        if d is None:
            # we are probably in the middle of a (seeded) random
            # computation, and we do not want the distance function
            # to mess with that state.
            random_state = random.getstate()
            try:
                d = self._compute_distance(i, j)
            finally:
                random.setstate(random_state)
            computed[index] = d
        return d

    def matrix(self):
        raise ValueError('LazyDistances does not support matrix()')

    def _compute_distance(self, i, j):
        raise ValueError('_compute_distance was not implemented')


def _shuffled_range(n):
    # returns all numbers from [0, ..., n - 1] in random order, never returning any number twice.

    # basically a Fisher-Yates shuffle that does not materialize the data, which means it's especially suited for
    # k << n, where k is the count of random numbers actually retrieved.

    # performs surprisingly well even if all random numbers are retrieved. getting all available numbers from
    # shuffled_range(10^7) only takes only 70% longer than generating just the raw 10 million random numbers.

    a = dict()

    def nth(k):
        return a.get(k, k)

    for i in range(n - 1):
        ai = nth(i)

        j = random.randint(i, n - 1)
        aj = nth(j)

        a[j] = ai
        yield aj

    yield nth(n - 1)


def _shuffled_tuples(*t):
    # like _shuffled_range, but not returning integers, but tuples
    # of integers within given ranges.

    # we map the tuple values to a linear index, then use _shuffled_range.

    # e.g. for t = (2, 3), we map:
    # 0 -> (0, 0); 1 -> (1, 0); 2 -> (0, 1)
    # 3 -> (1, 1); 4 -> (0, 2); 5 -> (1, 2)

    n = 1
    for x in t:
        n *= x
    indices = iter(_shuffled_range(n))

    while True:
        n = next(indices)
        r = []
        for x in t:
            r.append(n % x)
            n = n // x
        yield r


def _unmapped(u, v, distance):
    # maps each object in u to the most similar object in v
    # and returns a version of v from which all unmapped objects
    # have been removed.

    mapped = [False] * len(v)
    for uu in u:
        min_d = None
        min_i = None
        for i, vv in enumerate(v):
            if uu == vv:
                d = 0
            else:
                d = distance(uu, vv)
            if min_d is None or d < min_d:
                min_d = d
                min_i = i
        mapped[min_i] = True
    return [vv for m, vv in zip(mapped, v) if m]


def _agoras(n, k, distance):  # see [Rangel2016]
    gamma = 0.577215664901532  # Euler-Mascheroni constant
    m = int(math.ceil(k * (math.log(k) + gamma)))
    r = k * math.log(k) + gamma * k
    p = tuple(range(n))

    if r > n:
        # if k (and thus r) is very large in regard to n, we fall
        # back to simple sampling, since AGORAS is slow then.
        return random.sample(p, k)

    while True:
        s = [random.sample(p, min(int(r), n)) for _ in range(m)]
        for i in range(m - 1):
            s[i + 1] = _unmapped(s[i], s[i + 1], distance)
            if len(s[i + 1]) < k:
                r += r * (m - (i + 1)) / m
                break
        if len(s[-1]) > k:
            r *= 0.95
        elif len(s[-1]) == k:
            return s[-1]


class SplitCriterion(object):
    # note that as this runs as part of an O(n) algorithm, this
    # should not introduce an O(n^2) algorithm. see [Desgraupes2013]
    # and [Greutert2003] for possible algorithms,

    def should_split(self, siblings, merged, unmerged, distance):
        raise NotImplementedError()


class ApproximateSilhouetteSplitCriterion(SplitCriterion):
    # a fast, approximate version of the Silhouette index (see e.g.
    # [Desgraupes2013], that operates on medoids instead of points,
    # thereby reducing its runtime to O(nk) as opposed to O(n^2).

    def __init__(self, last_criterion=None):
        self._last_criterion = last_criterion

    def should_split(self, siblings, merged, unmerged, distance):
        try:
            criterion = self._approximate_global_silhouette_index(
                siblings + unmerged, distance)
        except InfiniteSilhouette:
            # zero distance between two clusters, do not accept split.
            return False, None

        # if the index is bigger than before, then more clusters are
        # in the right places than before, and we accept the split.
        if self._last_criterion is None or criterion > self._last_criterion:
            return True, ApproximateSilhouetteSplitCriterion(criterion)
        else:
            return False, None

    def _approximate_global_silhouette_index(self, clusters, distance):
        if len(clusters) <= 1:
            return -1.
        else:
            return fsum(self._approximate_mean_silhouette_widths(clusters, distance)) / len(clusters)

    def _approximate_mean_silhouette_widths(self, clusters, distance):
        d_in = self._approximate_within_distances(clusters, distance)
        d_out = self._approximate_mins_of_betweens_distances(clusters, distance)
        # the mean is just s(i) here, as we only use medoids for approximation.
        return (_silhouette(a, b) for a, b in zip(d_in, d_out))

    def _approximate_within_distances(self, clusters, distance):
        for c in clusters:
            s, n = c.within(distance)
            if n == 1:
                yield None
            else:
                yield s / (n - 1)

    def _approximate_mins_of_betweens_distances(self, clusters, distance):
        def medoids():
            for i, a in enumerate(clusters):
                yield i, a.medoid

        def other_medoids(i):
            for j, c in enumerate(clusters):
                if i != j:
                    yield c.medoid

        def other_members(i):
            for j, c in enumerate(clusters):
                if i != j:
                    for p in c.members:
                        yield p

        other = other_medoids  # fast version

        for i, a in medoids():
            yield _robust_min((distance(a, b) for b in other(i)))

AutomaticSplitCriterion = ApproximateSilhouetteSplitCriterion


class _Cluster:
    def __init__(self, medoid, members):
        self.medoid = medoid
        self.members = members
        self._within = None

    def translate(self, i_to_i0):
        return _Cluster(i_to_i0[self.medoid], [i_to_i0[i] for i in self.members])

    def within(self, distance):
        if self._within is None:
            # s_w is the sum of within-cluster (point to its medoid) distances.
            m = self.medoid
            s_w = fsum(distance(i, m) for i in self.members if i != m)
            n_w = len(self.members)
            self._within = (s_w, n_w)

        return self._within


class _Medoids:
    def __init__(self, clusterer, k):
        distance = clusterer._distance_lambda()
        n = clusterer._n

        self._n = n
        self._k = k
        self._distance = distance
        self._reset_random_swap()

        self._selected = _agoras(n, k, distance)
        self._selected.sort()

        self._clusters = [None] * n
        self._cost = fsum(self._update_clusters(self._unselected))
        self._debug = clusterer.debug

    def clusters(self):
        clusters = self._clusters
        solution = []
        for i in self._selected:
            members = [j for j in self._unselected if clusters[j][0] == i]
            # preserve the original order of the elements by inserting i.
            bisect.insort(members, i)
            solution.append(_Cluster(i, members))
        return solution

    @property
    def _unselected(self):
        selected = self._selected
        k = 0

        z = selected[k]
        k += 1
        for i in range(self._n):
            if i == z:
                if k < len(selected):
                    z = selected[k]
                    k += 1
                else:
                    z = -1
            else:
                yield i

    def _reset_random_swap(self):
        self._random_swap = iter(_shuffled_tuples(self._k, self._n - self._k))

    def _next_random_swap(self):
        # we modify ClaraNS by keeping track of the randomly picked swaps and not trying the same swap twice if no
        # improvement was made in the meantime. this is where the next not-yet-picked tuple is produced.

        n_i, h = next(self._random_swap)

        for j in self._selected:
            if h >= j:
                h += 1

        return self._selected[n_i], h

    def _update_clusters(self, a):
        selected = self._selected
        clusters = self._clusters
        distance = self._distance

        for j in a:
            s1, d1, s2, d2 = _smallest2(distance(i, j) for i in selected)
            i1 = selected[s1]
            i2 = selected[s2]
            assert i1 != i2
            clusters[j] = (i1, i2)
            yield d1

    def cost(self):
        return self._cost

    def swap(self):
        try:
            i, h = self._next_random_swap()
        except StopIteration:
            self._debug('all swaps tried')
            return False

        self._debug('eval swap', i, h)

        # try to swap medoid i with non-medoid h
        clusters = self._clusters
        distance = self._distance

        # we differentiate fast_updates and slow_updates. fast_updates
        # need to update only the second-nearest medoid. slow_updates
        # need to update the nearest and second-nearest medoid.
        fast_updates = []

        def calculate_t():
            # i attaches to a medoid
            yield min(distance(i, j) for j in chain(self._selected, [h]) if j != i)

            # h detaches from its medoid
            yield -distance(h, clusters[h][0])

            # look at all other points
            for j in self._unselected:
                if j == h:
                    continue
                # see [Ng1994] for a description of the following calculations
                n1, n2 = clusters[j]  # nearest two medoids
                dh = distance(j, h)  # d(Oj, Oh)
                if n1 == i:  # is j in cluster i?
                    d2 = distance(j, n2)  # d(Oj, Oj,2)
                    if dh >= d2:  # case (1); j does not go to h
                        yield d2 - distance(j, i)
                        fast_updates.append((j, n2))
                    else:  # case (2); j goes to h
                        yield dh - distance(j, i)
                        fast_updates.append((j, h))
                else:
                    k = clusters[j][0]
                    d2 = distance(j, k)
                    if dh >= d2:  # case (3)
                        # j stays in current cluster. second nearest medoid
                        # to j might change with the introduction of h though.
                        fast_updates.append((j, k))
                    else:  # case (4)
                        yield dh - d2
                        fast_updates.append((j, h))

        t = fsum(calculate_t())

        if t < 0:  # swap is an improvement?
            self._debug('ACCEPT swap t:%f' % t, i, h)
            self._cost += t

            selected = self._selected
            del selected[selected.index(i)]
            bisect.insort(selected, h)

            slow_updates = [i]  # update i's distances to medoids
            for j, m in fast_updates:
                if m == i:
                    slow_updates.append(j)
                else:
                    min_d = None
                    min_k = None
                    for k in selected:
                        if k != m:
                            d = distance(k, j)
                            if min_d is None or d < min_d:
                                min_d = d
                                min_k = k
                    assert m != min_k and min_k is not None
                    clusters[j] = (m, min_k)

            # update other second distances.
            for _ in self._update_clusters(slow_updates):
                pass  # ignore distances (no influence on cost here).

            # we swapped, so we want to allow previously used partners.
            self._reset_random_swap()

            return True
        else:
            return False


class _Clusterer:
    debug_output = False

    def __init__(self, n, i_to_i0, medoid0, siblings, p0, d0):
        self._n = n
        self._i_to_i0 = i_to_i0
        self._medoid0 = medoid0
        self._siblings = siblings
        self._p0 = p0
        self._d0 = d0

    def _distance_lambda(self):
        d0 = self._d0
        i_to_i0 = self._i_to_i0

        def distance(i, j):
            return d0(i_to_i0[i], i_to_i0[j])

        return distance

    def debug(self, s, *i):
        if self.debug_output:
            print(s, [self._p0[self._i_to_i0[j]] for j in i])

    def with_k(self, k):
        # this implements CLARANS as described in [Ng1994]. we modify it
        # by doing an AGORAS seed in _Medoids().

        n = self._n
        # [Ng1994] recommends the following values
        num_local = 2  # number of local minima to search for
        max_neighbours = min(max(0.0125 * k * (n - k), 250), k * (n - k))

        min_cost_medoids = None
        for i in range(num_local):
            medoids = _Medoids(self, k)

            self.debug('new local %f' % medoids.cost())
            j = 1
            while j <= max_neighbours:
                if medoids.swap():
                    self.debug('NEW MEDOIDS (%f)' % medoids.cost(), *medoids._selected)
                    j = 1
                else:
                    j += 1

            self.debug('end local %f' % medoids.cost())
            if min_cost_medoids is None or medoids.cost() < min_cost_medoids.cost():
                min_cost_medoids = medoids

        return min_cost_medoids.clusters()

    def without_k(self, criterion):
        # we estimate k using the approach described in [Hamerly2003].

        # this chunks the points (0, 1, ..., n - 1) into clusters. each point i
        # corresponds to a global point index i_to_i0[i]. d0 is a distance function
        # that takes two global point indices.

        n = self._n
        i_to_i0 = self._i_to_i0

        if n < 2:
            return [[i_to_i0[0]]]

        clusters = self.with_k(2)
        clusters0 = [c.translate(i_to_i0) for c in clusters]

        merged = _Cluster(self._medoid0, list(chain(*[c.members for c in clusters0])))

        split, new_criterion = criterion.should_split(
            self._siblings, merged, clusters0, self._d0)

        if self.debug_output:
            print([[self._p0[i] for i in c.members] for c in self._siblings + clusters0], split, new_criterion)

        if not split:
            return [[i_to_i0[i] for i in range(n)]]
        else:
            r = []
            for i, c in enumerate(clusters):
                t = clusters0[i].members
                d = clusters0[1 - i]

                sub = _Clusterer(len(t), t, clusters0[i].medoid, self._siblings + [d], self._p0, self._d0)
                r.extend(sub.without_k(new_criterion))
            return r


def optimize(p, k, distances, mode='clusters', seed=12345, granularity=1.):
    if k == 1:
        return [p]

    random_state = random.getstate()
    try:
        # we want the same output on every call on the same data, so we use
        # a fixed random seed at this point.
        random.seed(seed)

        clusterer = _Clusterer(
            len(p), tuple(range(len(p))), None, [], p, distances.distance)

        if isinstance(k, tuple) and len(k) == 2:
            criterion = k[0](**k[1])
            assert isinstance(criterion, SplitCriterion)
            clusters = clusterer.without_k(criterion)
        elif isinstance(k, int):
            clusters = [c.members for c in clusterer.with_k(k)]
        else:
            raise ValueError('illegal parameter k "%s"' % str(k))

        # sort clusters by order of their first element in the original list.
        clusters = sorted(clusters, key=lambda c: c[0])

        if mode == 'clusters':
            return list(map(lambda c: map(lambda i: p[i], c), clusters))
        elif mode == 'components':
            return _components(clusters, len(p))
        else:
            raise ValueError('illegal mode %s' % mode)
    finally:
        random.setstate(random_state)


class MergeCriterion(object):
    def __init__(self, distances, n):
        self.distances = distances
        self.n = n

    def merge(self, clusters, i, j, d_min, save):
        raise NotImplementedError()

    def _fast_distance(self):
        distances = self.distances
        return lambda x, y: distances[_index(max(x, y), min(x, y))]


class FixedDistanceCriterion(MergeCriterion):
    def __init__(self, distances, n, merge_limit):
        super(FixedDistanceCriterion, self).__init__(distances, n)
        self._merge_limit = merge_limit

    def merge(self, clusters, i, j, d_min, save):
        return d_min <= self._merge_limit


class _DunnMergeCriterion(MergeCriterion):
    # implements a Dunn index, as for example described in [Desgraupes2013].

    def __init__(self, distances, n, merge_limit=None):
        # merge_limit: do not merge points above this distance; if the merged
        # distance falls above this limit, the clustering is stopped and the
        # best clustering so far is returned.

        super(_DunnMergeCriterion, self).__init__(distances, n)

        self._diameters = [0.] * n
        self._max_diameter = 0.
        self._best_dunn = None

        self._merge_limit = merge_limit

    def merge(self, clusters, i, j, d_min, save):
        # save the current partition if it's better than before.

        dunn = (d_min, self._max_diameter)
        if self._best_dunn is None or _ratio_bigger_than(dunn, self._best_dunn):
            save()
            if self._max_diameter > 0.:
                self._best_dunn = dunn

        # now perform the merge.

        if self._merge_limit is not None and d_min > self._merge_limit:
            return False

        distance = self._fast_distance()
        new_diameter = max(distance(x, y) for x in clusters[i] for y in clusters[j])

        diameters = self._diameters
        diameters[i] = max(diameters[i], diameters[j], new_diameter)
        diameters[j] = None
        self._max_diameter = max(self._max_diameter, diameters[i])

        return True


AutomaticMergeCriterion = _DunnMergeCriterion


def agglomerate(points_and_weights, k, distances, mode='clusters'):
    # this is an implementation of heap-based clustering as described
    # by [Kurita1991].

    # runs in O(N^2 log(N)) when N items are clustered, with memory
    # of O(N^2).

    # two notes on this implementation:

    # (1) we work with 0-based indices, whereas Kurita's pseudocode
    # uses 1-based indices.

    # (2) when comparing heap elements h[i], h[j], we actually
    # compare tuples of (distance, index, pair of elements), which
    # guarantees that clusterings will produce the same results
    # no matter how the input data is ordered, and that h[i] != h[j]
    # as long as i != j.

    # parameters:

    # points: list of points to cluster
    # k: number of clusters to form or None for automatic detection
    # distances: an instance of PrecomputedDistances
    # mode: 'clusters' returns clusters, 'dominant' returns one dominant
    # representant of each cluster only, 'components' returns the index of
    # the cluster each element is in for each element.

    if mode == 'dominant':
        points, weight_ = points_and_weights
        weight = [x for x in weight_]
    else:
        points = points_and_weights

    clusters = [[i] for i in range(len(points))]

    def shiftdown(s, heap, where):
        e = len(heap) - 1

        i = s
        j = 2 * i + 1  # i.e. 2 * (i + 1) - 1
        if j > e:
            return

        x, p, _ = xp = heap[i]

        while j <= e:
            if j < e and heap[j] > heap[j + 1]:
                j += 1
            if xp <= heap[j]:
                break

            xx, pp, _ = heap[i] = heap[j]
            where[pp] = i

            i = j
            j = 2 * i + 1

        heap[i] = xp
        where[p] = i

    def shiftup(s, heap, where):
        i = s
        j = (i + 1) // 2 - 1
        if j < 0:
            return

        x, p, _ = xp = heap[i]

        while j >= 0:
            if heap[j] <= xp:
                break

            xx, pp, _ = heap[i] = heap[j]
            where[pp] = i

            i = j
            j = (i + 1) // 2 - 1

        heap[i] = xp
        where[p] = i

    def update(s, xp, heap, where):
        xxpp = heap[s]
        assert xp != xxpp

        if xp > xxpp:
            heap[s] = xp
            shiftdown(s, heap, where)
        else:
            heap[s] = xp
            shiftup(s, heap, where)

    def remove(s, heap, where):
        if s == len(heap) - 1:
            heap = heap[:-1]
        else:
            xx, pp, _ = xxpp = heap[-1]
            heap = heap[:-1]
            where[pp] = s
            update(s, xxpp, heap, where)

        return heap

    def unmerged_pairs(i, j, n):
        # yields all unmerged pairs (1, i), (2, i), ...
        # except for (i, i) and (i, j)

        # example of unmerged_pairs() output (none merged yet):
        # n = 4, i = 1, j = 3
        # unmerged_pairs(1, 3, 4) -> (1, 0), (2, 1)
        # unmerged_pairs(3, 1, 4) -> (3, 0), (3, 2)

        for r in range(i):  # all (i, _)
            if r != j and clusters[r]:  # r is not yet merged?
                yield _index(i, r)

        # skip (i, i)

        for r in range(i + 1, n):  # all (_, i)
            if r != j and clusters[r]:  # r is not yet merged?
                yield _index(r, i)

    def reduce():
        n = len(points)
        triangular_distance_matrix = distances.matrix()

        if isinstance(k, tuple) and len(k) == 2:
            criterion = k[0](triangular_distance_matrix, n, **k[1])
            assert isinstance(criterion, MergeCriterion)
            n_clusters_target = 1
        elif isinstance(k, int):
            criterion = None
            n_clusters_target = k
        else:
            raise ValueError('illegal k "%s"' % str(k))

        pairs = [(points[i], points[j]) for i in range(n) for j in range(i)]
        lookup = [(i, j) for i in range(n) for j in range(i)]

        where = list(range(len(triangular_distance_matrix)))
        heap = [(d, z, u) for d, z, u in zip(
            triangular_distance_matrix, where, pairs)]

        for s in range(len(heap) // 2 - 1, -1, -1):  # ..., 1, 0
            shiftdown(s, heap, where)

        n_clusters = n

        # if the criterion does not call save(), "best" is always the current (last) configuration.
        # save() allows to put a different configuration into "best" and keep on clustering and
        # return the "best" configuration later on as result.

        if mode in ('clusters', 'components'):
            dominant = False
            best = [clusters]

            def save():  # save current configuration
                best[0] = [c[:] for c in clusters if c]

            def result():
                best_clusters = best[0]

                # sort, so clusters appear in order of their first element appearance in the original list.
                r = sorted([sorted(c) for c in best_clusters if c], key=lambda c: c[0])

                if mode == 'components':
                    return _components(r, n)
                elif mode == 'clusters':
                    return [[points[i] for i in c] for c in r]
        elif mode == 'dominant':
            dominant = True
            best = [clusters, weight]

            def save():  # save current configuration
                best[0] = [c[:] for c in clusters if c]
                best[1] = weight[:]

            def result():
                best_clusters, best_weight = best
                prototypes = [(points[i], best_weight[i], c) for i, c in enumerate(best_clusters) if c is not None]
                return sorted(prototypes, key=lambda t: t[1], reverse=True)  # most weighted first
        else:
            raise ValueError('illegal mode %s' % mode)

        while len(heap) > 0 and n_clusters > n_clusters_target:
            d, p, _ = heap[0]

            i, j = lookup[p]

            if dominant:
                if weight[j] > weight[i]:  # always merge smaller (j) into larger, dominant (i)
                    i, j = j, i
            elif i > j:
                i, j = j, i  # merge later chunk to earlier one to preserve order

            if criterion and not criterion.merge(clusters, i, j, d, save):
                break

            heap = remove(where[p], heap, where)  # remove distance (i, j)

            # look at each connection to i, and each connection to j, so that we look at the same
            # points connection to the cluster, i.e. (a=(1, i), b=(1, j)), (a=(2, i), b=(2,i)), etc.
            for a, b in zip(unmerged_pairs(i, j, n), unmerged_pairs(j, i, n)):
                # first, remove the distance to j from the heap, as only the distance to i should
                # remain, as the new cluster will be i.

                y, py, u = heap[where[b]]
                heap = remove(where[b], heap, where)

                # now update the distance to i with j's distance, if j was a shorter distance. this
                # implements a "single linkage" clustering, where the distance of an outside point to
                # the cluster is always the shortest distance from that outside point to any point in
                # the cluster.

                # in the "dominant" mode, we do not want this. instead, we want to keep the distance
                # from outside points to the dominant element in the cluster, which is always "a",
                # so that the clustering depends on the distance of cluster center to new elements.
                # using single linkage with "dominant" would fray the borders of the clustering, so
                # that the dominant elements are not really dominant anymore.

                if not dominant:  # use single linkage?
                    x, px, _ = heap[where[a]]
                    if y < x:  # compare only values here, and not tuples (x, p)
                        update(where[a], (y, px, u), heap, where)

            if dominant:
                weight[i] += weight[j]
                weight[j] = 0

            clusters[i].extend(clusters[j])
            clusters[j] = None

            n_clusters -= 1

        return result()

    return reduce()


class _KMeans:
    def __init__(self, x, d, epsilon):
        self.x = x
        self.d = d
        self.epsilon = epsilon

    def _pick_initial(self):
        # use k-means++, see [Arthur2007]

        x = self.x
        d = self.d

        candidates = list(range(len(x)))

        i = random.randint(0, len(candidates) - 1)
        new_centroid = x[candidates[i]]
        yield new_centroid

        def swap_delete(a, i):
            j = len(a) - 1
            a[i] = a[j]
            del a[j]

        def random_choice(m, p):  # weighted random choice
            r = random.uniform(0, m)
            for i, z in enumerate(chain(p, [None])):
                if z is None:
                    return i - 1
                if r < z:
                    return i
                r -= z

        def d2(x, y):
            distance = d(x, y)
            return distance * distance

        swap_delete(candidates, i)

        distances = [d2(new_centroid, x[candidate]) for candidate in candidates]
        sum_of_distances = sum(distances)
        while True:
            i = random_choice(sum_of_distances, distances)
            new_centroid = x[candidates[i]]
            yield new_centroid

            swap_delete(candidates, i)
            sum_of_distances -= distances[i]
            swap_delete(distances, i)

            for i, candidate_distance in enumerate(zip(candidates, distances)):
                candidate, old_distance = candidate_distance
                new_distance = d2(new_centroid, x[candidate])
                if new_distance < old_distance:
                    distances[i] = new_distance
                    sum_of_distances -= old_distance - new_distance

    def _distances(self, c):
        d = self.d
        k = len(c)

        between = {}
        for j1, c1 in enumerate(c):
            z = j1 * k
            for j2, c2 in enumerate(c[:j1]):
                between[z + j2] = d(c1, c2)

        return lambda x, y: between[max(x, y) * k + min(x, y)]

    def _kmeans(self, k):
        # implements an improved version of kmeans, see [Hamerly2010].
        x = self.x
        d = self.d

        assert k <= len(x)

        # pick initial clusters. actually quite an important step.
        c = list(islice(self._pick_initial(), 0, k))
        assert len(c) == k

        q = [0] * len(c)
        cc = [[0] * len(x[0]) for _ in range(k)]

        a = [0] * len(x)
        u = [0] * len(x)
        l = [0] * len(x)

        for i, xi in enumerate(x):
            ai, u[i], _, l[i] = _smallest2(d(xi, cj) for cj in c)
            q[ai] += 1
            cc[ai] = _pairwise_sum(cc[ai], xi)
            a[i] = ai

        s = [0] * len(c)
        p = [0] * len(c)
        change = None

        while change is None or change > self.epsilon:
            # find cluster distances
            cd = self._distances(c)
            s = [min(cd(j1, j2) for j2 in range(k) if j2 != j1) for j1 in range(k)]

            # find new assignments
            for i, ai in enumerate(a):
                m = max(s[ai] / 2., l[i])

                if u[i] > m:
                    xi = x[i]
                    u[i] = d(xi, c[ai])

                    if u[i] > m:
                        new_ai, u[i], _, l[i] = _smallest2(d(xi, cj) for cj in c)

                        if new_ai != ai:
                            q[ai] -= 1
                            q[new_ai] += 1
                            cc[ai] = [a - b for a, b in zip(cc[ai], xi)]
                            cc[new_ai] = [a + b for a, b in zip(cc[new_ai], xi)]

                            a[i] = new_ai

            # move centers
            empty_cluster = False

            for j in range(len(c)):
                qj = q[j]
                if qj == 0:
                    empty_cluster = True
                    break
                c_old = c[j]
                c_new = [ccj / qj for ccj in cc[j]]
                distance = d(c_old, c_new)
                c[j] = c_new
                p[j] = distance

            if empty_cluster:
                break

            # update bounds
            r1, p1, r2, p2 = _largest2(p)
            for i, ai in enumerate(a):
                u[i] += p[ai]
                if r1 == ai:
                    l[i] -= p2
                else:
                    l[i] -= p1

            change = sum(p)

        # compute an approximate silhouette index
        within = [0] * len(c)
        for i, ai in enumerate(a):
            within[ai] += d(x[i], c[ai])
        for j in range(len(c)):
            if q[j] == 1:
                return a, -1.  # no good config
            within[j] /= q[j] - 1

        silhouette = fsum(_silhouette(a, b) for a, b in zip(within, s)) / len(c)
        return a, silhouette

    def _optimize(self, solutions):
        best_a = None
        best_silhouette = None
        best_k = None

        for a, silhouette, k in solutions():
            if best_silhouette is None:
                pass
            elif silhouette <= best_silhouette:
                break
            best_silhouette = silhouette
            best_a = a
            best_k = k

        return best_a, best_silhouette, best_k

    def with_k(self, k):
        def solutions():
            while True:
                a, s = self._kmeans(k)
                yield a, s, k

        return self._optimize(solutions)

    def without_k(self):
        def solutions():
            k = 2
            while k < len(self.x):
                yield self.with_k(k)
                k += 1

        return self._optimize(solutions)


def _squared_euclidean_distance(a, b):
    s = None
    for x, y in zip(a, b):
        d = x - y
        if s is None:
            s = d * d
        else:
            s += d * d
    return s


def _clusters(x, a, k):
    clusters = [[] for _ in range(k)]
    add = [c.append for c in clusters]
    for i, j in enumerate(a):
        add[j](x[i])
    return clusters


def kmeans(x, x_repr, k, mode, seed, epsilon):
    assert len(x) == len(x_repr)

    random.seed(seed)
    km = _KMeans(x, _squared_euclidean_distance, epsilon)

    if k is None:
        a, _, k = km.without_k()
    else:
        assert 1 < k < len(x)
        a, _, k = km.with_k(k)

    if mode == 'clusters':
        return _clusters(x_repr, a, k)
    elif mode == 'components':
        return a
    else:
        raise ValueError('illegal mode %s' % mode)
